All Questions
8 questions
0
votes
0
answers
20
views
Java Data Collector for Stack Overflow
This application collects data from Stack Overflow using the Stack Exchange API.
It retrieves questions, answers, and comments related to Java programming for analysis.
Features include:
Collecting ...
2
votes
1
answer
167
views
Differences between versions 1.x and 2.x of the Stack Exchange API?
I had written a Java Wrapper for the Stack Exchange API, version 1.x, Which was working perfectly.
But, since 12 May 2014, services for version 1.x have been shutdown and my Wrapper stopped working.
...
2
votes
1
answer
798
views
How to handle default compression on response with Java's HttpURLConnection? [duplicate]
I sent a request for question with no parameters to
https://api.stackexchange.com/2.2/questions?order=desc&sort=activity&site=stackoverflow
I received a response of 9764 bytes stored in ...
6
votes
2
answers
1k
views
StackExchange API Java SDK
This project aims to provide a Java wrapper to the Stack Exchange API.
SDK supports Stack Exchange API V2.2
Getting Started
There are two interfaces to the library.
Query Interface
Facade ...
8
votes
1
answer
729
views
StackExchange API Java wrapper
Screenshot / Code Snippet
StackExchangeApi api = new StackExchangeApi(key);
api.authorize(authToken);
StackExchangeSite siteService = api.getSiteService(StackExchangeSite.STACK_OVERFLOW);
Response&...
3
votes
1
answer
254
views
Encoding problem while accessing the API using Java
Trying to call an API URL from a Java application, I'm having problems accessing the contents of the URL.
I can access other sites through my program but not the Stack Exchange site.
But I can call ...
5
votes
1
answer
148
views
The StackWrap4J java wrapper gives nothing but `JSONException`s?
I'm using the StackWrap4J java wrapper for the Stack Overflow API.
But every code I try, that uses methods of this java wrapper, ends with this JSONException:
net.sf.stackwrap4j.json.JSONException: ...
0
votes
1
answer
88
views
Coding error at open URL
Hi,
I have the following method to open a URL API
String c="";
URL direccionURL;
try {
direccionURL = new URL("http://api.stackoverflow.com/1.0/users/523725");
BufferedReader in = new ...