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Questions tagged [getting-started]

For information on the fundamentals of developing solutions with the Stack Exchange API

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109 votes
3 answers
24k views

Method List All API methods can be found at https://api.stackexchange.com/docs. Global Method Parameters All methods accept the following parameters: type=jsontext: responds with mime-type text/json. ...
21 votes
5 answers
1k views

What constitutes abuse? Making an undue number of requests in a short span of time, or regularly exceeding a request quota during "normal" use. Guidelines for polling We realize that a great ...
6 votes
1 answer
326 views

How I can connect my extension to the API? I tried to use this example code for connecting: SE.init({ clientId: 1, key: '?', channelUrl: '?', complete: function (data) { alert('...
140 votes
3 answers
31k views

The Stack Exchange API is based on HTTP and URLs, just like the web page you're browsing now. Except instead of HTML, the responses are all in JSON. Let's say we wanted to call the /info method: https:...
5 votes
2 answers
495 views

I am trying to get the amount of reputation that a user has. I have established that I need to use this url: https://api.stackexchange.com/2.1/users/1272330?order=desc&sort=reputation&site=...
32 votes
1 answer
11k views

I see the Stack Exchange API but I'm unable to understand it. I don't think there is any fundamental tutorial showing how to use Stack Overflow fully in the API documentation. I want some fundamental ...
6 votes
2 answers
475 views

I'm just getting started messing around with the SO API. I haven't worked with JSON before, and I am getting a strange result from a basic call (No API Key). WebClient stackClient = new WebClient(); ...
4 votes
2 answers
2k views

I am new to StackApps. I have created an account and I have got an API key. Now my question is, how can I access user accounts? I'm interested in posted questions and answers. Is there a way to post ...
4 votes
3 answers
341 views

I want to know if my slender grasp of the latter will help me learn about the former.