Trying to call an API URL from a Java application, I'm having problems accessing the contents of the URL.

I can access other sites through my program but not the Stack Exchange site. But I can call the URL directly from the browser and get data.

This is my program and output is in encrypted form. I want to get in a normal format.

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.URL;
import java.net.URLConnection;
import java.io.BufferedReader;

public class URLServlet {

    public static void main(String[] args) {
        try {
        URL urldemo = new URL("http://api.stackexchange.com/2.1/questions/1346?site=health.stackexchange.com&filter=withbody");
        URLConnection yc = urldemo.openConnection();
        BufferedReader in = new BufferedReader(new InputStreamReader(

        String inputLine;
        while ((inputLine = in.readLine()) != null)
        }catch(Exception e) {

        System.out.println("hello world");

The API responses are always compressed and the default compression is GZIP.

This means that you must use the proper GZIP-handling libraries to fetch the data.

So, instead of:

BufferedReader in = new BufferedReader (new InputStreamReader (
        yc.getInputStream () ));

You would use something more like:

BufferedReader in = new BufferedReader (new InputStreamReader (
        (new GZIPInputStream (yc.getInputStream () )) ));
| improve this answer | |
  • can i parse the information by adding tags to the same program and get the information which is required by me – Abheeshta Putta Jun 25 '15 at 9:30
  • You are going to have to give examples of what you mean by that, but that sounds like a separate question. For this question, is your encoding problem solved? – Brock Adams Jun 25 '15 at 9:32
  • ya it is solved i am getting all the data but i want o have selected data how can that be possible? – Abheeshta Putta Jun 25 '15 at 10:51
  • Open a new question. Show: (1) what you get, (2) what you want, and (3) what you tried. Also make sure the question meets the help center requirements. – Brock Adams Jun 25 '15 at 11:02

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