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I am trying to query stackoverflow and route it to my website via the following

<?php
require_once './stackphp_source_0.4/src/api.php';
require_once './includes/function.php';

// Begin by getting a Site object for Stack Overflow.
// We can use 'stackoverflow' or 'stackoverflow.com' here.

$question = new QuestionRequest('http://www.stackoverflow.com', null);
$question = $question->Search("C#");

// paged Response object
$page = $question->Answers()->Exec(); 

?>


<html>
    <head>
        <?php
            include("includes/bootstrap.php");
        ?>
        
          <meta http-equiv="content-type" content="text/html; charset=UTF-8">
        <title>Stack.PHP - User's Questions</title>
  <!-- <link rel='stylesheet' type='text/css' href='../common/style.css' /> -->

    </head>
    <body>
        <?php include("includes/banner.php"); ?>
        
        <div class="main_content">
              <h2>Questions Asked By User #1 on Stack Overflow</h2>
              
              <?php echo $page->Fetch(); ?>
        </div>


    <?php include("includes/script_includes.php"); ?>
    </body>
</html>

I keep getting the error

Curl was unable to retrieve the data from the specified URL.

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1 Answer 1

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First of all, you should be using the latest version of Stack.PHP, which is version 0.5. You can download a tarball here:

https://launchpad.net/stackphp/0.5/0.5/+download/stackphp-0.5-source.tar.gz

The only file you need to include is api.php which is in the src/ directory.

You will almost never need to create a Request object yourself since you can obtain it from a Site object. You can do that with:

$site = API::Site('stackoverflow');

Now you can use $site to access the methods available on that site, most of which return a subclass of Request:

$request = $site->Search('C#');

Once you have a request, you need to convert it into a response. This is done as follows:

$response = $request.exec();

You can then enumerate the items in the response with:

while($q = $response->Fetch(FALSE))
{
    // do something with $q here
}

For example, echo $q['title'] will display the question's title.

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