Timeline for Finding a user given their (exact) display name
Current License: CC BY-SA 2.5
16 events
| when toggle format | what | by | license | comment | |
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| Apr 13, 2017 at 12:25 | history | edited | CommunityBot |
replaced http://stackapps.com/ with https://stackapps.com/
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| Sep 15, 2011 at 12:34 | comment | added | codeka | @hhh: this was from over a year ago... my app is no longer online anyway, it basically did what you can now see here: stackexchange.com/leagues | |
| Sep 14, 2011 at 18:38 | comment | added | user8160 | url broken in the first sentence. | |
| Jul 9, 2010 at 17:21 | comment | added | Sky Sanders | you may now reformat your q into a how-to as there is but one means to this end. you may want to rephrase the q to something like 'how to find all users with exactly matching display name' or some such. a dev-tip tag might not be a bad idea either. | |
| Jul 9, 2010 at 17:14 | comment | added | Sky Sanders |
min/max on users by name is now case insensitive resulting in a viable 'exact match'. e.g. min=john&max=john see stackapps.com/questions/1060
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| Jul 8, 2010 at 18:33 | answer | added | Sky Sanders | timeline score: 1 | |
| Jun 8, 2010 at 23:18 | comment | added | codeka | @InfinitesLoop: that's my idea as well, just as a way to identify yourself via your name rather than ID. Of course, there's some people with the same name, but in my experience they're a minority and it's easy to show a list of all the people with the same name if that's the case. | |
| Jun 8, 2010 at 15:39 | comment | added | InfinitiesLoop | I was just hoping for this feature as well. I don't need to authenticate the user, I just want them to type a user by their name. Looks like there's a non-ideal way of doing it. It would be nice if the API had this scenario explicitly handled somehow. | |
| Jun 7, 2010 at 7:45 | answer | added | codeka | timeline score: 5 | |
| Jun 7, 2010 at 7:35 | comment | added | codeka | @Soviut: It's not actually for authentication, the "registration" is just adding users to a list that my app monitors for reputation changes (among other things) - you can "register" any user you like. Basically just an easier method than having to find your user ID. | |
| Jun 7, 2010 at 6:53 | comment | added | balphaStaff♦ | @Soviut: The user's openid isn't public | |
| Jun 7, 2010 at 6:51 | comment | added | Soviut | Wouldn't it be better to identify them using their openID that they'd already have on Stack sites anyways? That way you also don't have to write your own authentication system. | |
| Jun 7, 2010 at 4:28 | comment | added | codeka |
@Dennis: the problem is that to get all of the exact matches for "John" I would have to download all 1,287 results from the API before displaying them to the user to choose. That's 43 requests... by adding an exact=true parameter, then I could do it in a single query.
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| Jun 7, 2010 at 4:26 | comment | added | Dennis Williamson | Your app could refilter what the API returns. | |
| Jun 7, 2010 at 4:23 | history | edited | codeka | CC BY-SA 2.5 |
edited body
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| Jun 7, 2010 at 4:13 | history | asked | codeka | CC BY-SA 2.5 |