Timeline for SEAPI - A lightweight Python wrapper for the Stack Exchange API
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
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| May 23, 2017 at 12:39 | history | edited | CommunityBot |
replaced http://stackoverflow.com/ with https://stackoverflow.com/
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| Jan 24, 2014 at 4:59 | comment | added | lifebalance | You are right, that's what I probably need to do. THanks, | |
| Jan 22, 2014 at 12:00 | comment | added | Piotr Migdal | I did click on the api.stackexchange.com you posted and it didn't respond to order parameter. As the SEAPI has no ambition beyond translating Pythonic queries to StackExchange API, there is little I can do. Maybe the other app uses a different query or takes all favourites (I guess, rarely more than a few thousands) and performs the sorting? I do not know. | |
| Jan 21, 2014 at 19:38 | comment | added | lifebalance |
Sorry, I am adding this here, but TimStone already deleted the other answer. The API seems to work okay for StackFavorites - stackapps.com/q/2438/12360. so.fetch("/users/{ids}/favorites",ids = [id], order="desc", sort="added", page=1) is what I am using, but it did not work.
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| Jan 21, 2014 at 18:58 | comment | added | Piotr Migdal | SEAPI is not under active development. But if you want some changes, why not forking the repository - I would be happy to accept some pull requests. :) | |
| Dec 30, 2013 at 23:32 | history | edited | lifebalance | CC BY-SA 3.0 |
bolded Related
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| Dec 30, 2013 at 23:17 | comment | added | lifebalance | SEAPI is clean, efficient and a breath of fresh air compared to the other StackApps I've struggled with all night! It would be great if it incorporated authentication using requests_oauthlib. Is that already in the works? | |
| Dec 30, 2013 at 22:45 | review | First posts | |||
| Jan 29, 2014 at 22:32 | |||||
| Dec 30, 2013 at 22:32 | comment | added | Piotr Migdal |
x = so.fetch("/tags/{tag}/related", tag=tag1), y = so.fetch("/tags/{tag}/related", tag=tag2) and the rest is Python (e.g. get tag names and make set intersection, if it is what you have in mind).
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| Dec 30, 2013 at 22:26 | history | answered | lifebalance | CC BY-SA 3.0 |