A question about how the API returns users.

learn more… | top users | synonyms (1)

4
votes
1answer
89 views

Access to /users/recent/ (Recent Activity) through the API

Would it be possible to have access to a user Recent Activity? I know that this is not a public information on the website, but I think that most part is public. I only see one Activity that should ...
1
vote
1answer
61 views

Problem getting a users answers within a date range

This issue is similar to http://stackapps.com/questions/768/problem-getting-a-users-questions-within-a-date-range. Only this time I'm calling a different api and getting unexpected results. I'm ...
3
votes
1answer
98 views

Problem getting a users questions within a date range

I'm having a problem returning a list of users questions within a given timespan. I understand that the documentation ( http://api.stackoverflow.com/0.8/help/method?method=users/{id}/questions ) that ...
0
votes
1answer
292 views

What's the best way to mashup a social network with StackOverflow?

I’m experimenting with an integration project where I mashup a user’s LinkedIn connections and StackOverflow activity. Are there any relevant APIs on StackOverflow that could be used to integrate ...
1
vote
0answers
66 views

What's the default fromdate for the /users/{id}/reputation route?

I'm getting different amounts of positive-rep when I use the fromdate and todate parameters with the /users/{id}/reputation route than when I don't use those parameters and accept the defaults. I ...
3
votes
2answers
72 views

On /users method id parameter does not work

Calling /users method with id parameter returns a list of users and not the user expected. http://api.stackoverflow.com/0.8/users?id=23234 Could be a documentation "bug" on help page: ...
2
votes
1answer
61 views

/users/{id}/badges - multiple identical results

Each badge returned in the list of results from /users/{id}/badges already contains an award_count indicating how many times the badge was awarded for the particular user attached to the badge. In ...